从数据库中查询前9条,从第二条输出

select top 9 * from biao where ID not in (select top 1 ID from biao)

那么以此类推

从数据库中查询前9条,从第三条输出

select top 9 * from biao where ID not in (select top 3 ID from biao)



从数据库中查询前9条,从第四条输出

select top 9 * from biao where ID not in (select top 4 ID from biao)